Stay Update with us

Email Subscription for Get Latest Notification and MCQ Quiz

# Simplification: Quantitative Aptitude MCQ Question and Answer

## Simplification MCQ Question with Details Answer

Q1. 2.002 + 7.9 {(2.8 – 6.3 (3.6 – 1.5) + 15.6)}

(a) 2.002

(b) 4.2845

(c) 4.0843

(d) 42.845

 Answer: (d) 42.845Solution:  2.002 + 7.9 {(2.8 – 6.3 (3.6 – 1.5) + 15.6)}= 2.002 + 7.9 (2.8 – 6.3 × 2.1 + 15.6)= 2.002 + 7.9 (2.8 – 13.23 + 15.6)= 2.002 + 7.9 × 15.17= 2.002 + 40.843 = 42.845

Q2. The value of $3\div \left[ \left( 8-5 \right) \div \left\{ \left( 4-2 \right) +\left( 2+\frac{8}{13} \right) \right\} \right]$

(a) $\frac{15}{17}$

(b) $\frac{13}{17}$

(c) $\frac{15}{19}$

(d) $\frac{13}{19}$

 Answer: (b)Solution:$3\div \left[ \left( 8-5 \right) \div \left\{ \left( 4-2 \right) \div \left( 2+\frac{8}{13} \right) \right\} \right] $$=3\div \left[ 3\div \left\{ 2\div \frac{34}{13} \right\} \right]$$=3\div \left[ 3\div \frac{13}{17} \right] =3\div \frac{3\times 17}{13}$$=3\times \frac{13}{3\times 17}=\frac{13}{17} Q3. 9-1\frac{2}{9}\mathrm{of} 3\frac{3}{11}\div 5\frac{1}{7}\,\,\mathrm{of} \frac{7}{9}\,\,=? (a) \frac{5}{4} (b) 8 (c) 8\frac{32}{81} (d) 9  Answer: (b) 8Solution:9-1\frac{2}{9}\mathrm{of} 3\frac{3}{11}\div 5\frac{1}{7}\,\,\mathrm{of} \frac{7}{9}\,\,$$=\,\,9-\frac{11}{9}\,\,\mathrm{of} \frac{36}{11}\,\,\times \frac{1}{\frac{36}{7}\times \frac{7}{9}}$$=9-4 \times \frac{1}{4}\,\,=8 Q4. 777.07 + 77.77 + 0.77 + 7.07 + 7 + 77 = ? (a) 946.78 (b) 946.68 (c) 964.68 (d) 946.86  Answer: (c) 964.68Solution: Q5. Find the value of 999\frac{1}{7}+999\frac{2}{7}+999\frac{3}{7}+999\frac{4}{7}+999\frac{5}{7}+999\frac{6}{7} (a) 5997 (b) 5979 (c) 5994 (d) 6997  Answer: (a)Solution: 999\frac{1}{7}+999\frac{2}{7}+999\frac{3}{7}+999\frac{4}{7}+999\frac{5}{7}+999\frac{6}{7}$$=\,\,999+\frac{1}{7}\,\,+999+\frac{2}{7}+999+\frac{3}{7}+999+\frac{4}{7}+999+\frac{5}{7}+999+\frac{6}{7}$$6\times 999 +\,\,\frac{1+2+3+4+5+6}{7}\,\, =\,\,5994 +\,\,3 =5997 Q6. Find the value of \frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99} (a) \frac{10}{11} (b) \frac{9}{11} (c) \frac{5}{11} (d) \frac{7}{11}  Answer: (c)Solution: \frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}$$=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}$$=\frac{1}{2}\left( 1-\frac{1}{11} \right) \,\,=\frac{5}{11} Triks: \frac{1}{\mathrm{n}\left( \mathrm{n}+2 \right)}+\frac{1}{\left( \mathrm{n}+2 \right) \left( \mathrm{n}+4 \right)}+…. +\frac{1}{\left\{ \mathrm{n}\left( \mathrm{m}-2 \right) \right\} \left( \mathrm{n}+\mathrm{m} \right)}$$=\,\,\frac{1}{2}\left( \frac{1}{\mathrm{n}}-\frac{1}{\mathrm{n}+\mathrm{m}} \right)$

Q7. Find the value of  $0.\bar{3}+0.\bar{6}+0.\bar{7}+0.\bar{8}$

(a) $2\frac{3}{10}$

(b) $2\frac{2}{3}$

(c) $20.\overline{35}$

(d) $5\frac{3}{10}$

 Answer: (b)Solution: $0.\bar{3}+0.\bar{6}+0.\bar{7}+0.\bar{8}$$=\frac{3}{9}+\frac{6}{9}+\frac{7}{9}+\frac{8}{9}=\frac{3+6+7+8}{9}=\frac{24}{9}=2\frac{2}{3}$

Q8. 1/4th of number of boys and 3/8th of number of girls participated in annual sports of the school. What fractional part of total number of students participated?

(a) 32%

(b) 20%

(c) 36%

(e) None of the above

 Answer: (d)Solution:  total number of students participated = $\frac{\mathrm{B}}{4}+\frac{3\mathrm{G}}{8}$Required percentage = $\frac{\frac{\mathrm{B}}{4}+\frac{3\mathrm{G}}{8}}{\left( \mathrm{B}+\mathrm{G} \right)}\times 100 \%$Since, B and G are unknown ; Clearly given Data is  inadequate.

Q9. Simplify : $1+\frac{1}{1+\frac{2}{2+\frac{3}{1+\frac{4}{5}}}}$

(a) $1\frac{11}{17}$

(b) $1\frac{5}{7}$

(c) $1\frac{6}{17}$

(d) $1\frac{21}{17}$

 Answer: (a) $1\frac{11}{17}$Solution: 1st ⇒ $1+\frac{4}{5}=\frac{9}{5}$2nd ⇒ $2+\frac{3\times 5}{9}=\frac{11}{3}$3rd ⇒ $1+\frac{2\times 3}{11}=\frac{17}{11}$4th ⇒$1+\frac{11}{17}=1\frac{11}{17}$

Q10. . If x =  $1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}$ then, the value of $2\mathrm{x}+\frac{7}{4}$  is

(a) 3

(b) 4

(c) 5

(d) 6

 Answer: (c) 5Solution: 1st ⇒ $1+\frac{1}{2}=\frac{3}{2}$2nd ⇒ $1+\frac{2}{3}=\frac{5}{3}$3rd ⇒ $1+\frac{3}{5}=\frac{8}{5}$4th ⇒ $1+\frac{5}{8}=\frac{13}{8}$∴ $2\mathrm{x}+\frac{7}{4}=2\times \frac{13}{8}+\frac{7}{4}=5$

### Quiz-5: Ancient Indian History MCQ Questions with Answer

error: Content is protected !!